Question
A cylindrical container of radius 20 cm contains water of height of 3 m. Two meters down from the water level there is a hole of 0.5 cm in radius. Find the velocity and volume flow rate of water leaving the hole. Where does it strike the ground?
Answers
bobpursley
Torricelli's equation applies, since 2m>>1cm
v=sqrt(2g*2m)=2sqrtg
volume flow rate= v*area
where does it strike the ground? the hole is 1mhigh, time for water to fall 1m is given by h=1/2 g t^2 or t= sqrt(2/g)
distance horizontal from tank= v*t=2sqrtg*(sqrt(2/g)=2sqrt2 meters.
v=sqrt(2g*2m)=2sqrtg
volume flow rate= v*area
where does it strike the ground? the hole is 1mhigh, time for water to fall 1m is given by h=1/2 g t^2 or t= sqrt(2/g)
distance horizontal from tank= v*t=2sqrtg*(sqrt(2/g)=2sqrt2 meters.