Asked by Dave
                The mean starting salary for graduates in the spring of 2004 was $36,280.  Assume that the distribution of starting salaries follows the normal distribution with a standard deviation of $3,300.  What percent of the graduates have starting salaries between $35,000 and $40,000?
a. 5225
b. .0041
c. .1251
d. None of the above
            
            
        a. 5225
b. .0041
c. .1251
d. None of the above
Answers
                    Answered by
            Logan
            
    Copy and paste the question into Google and the answer is there. Looks like it will be d, but check it out yourself
    
                    Answered by
            Logan
            
    Here is the math
(35,000<X<40,000)=P((35,000-36,280)/3,300<(X-36,280)/3,300<(40,000-36,280)/3,300)=P(-0.3879<Z<1.1273)
=P(Z<1.1273)-P(Z<-0.3879)=0.8702-0.3491= 0.5211
    
(35,000<X<40,000)=P((35,000-36,280)/3,300<(X-36,280)/3,300<(40,000-36,280)/3,300)=P(-0.3879<Z<1.1273)
=P(Z<1.1273)-P(Z<-0.3879)=0.8702-0.3491= 0.5211
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