Asked by Jay
A kickball is kicked upward with an initial vertical velocity of 3.2 meters
per second. The height of the ball is given by
h=-9.8t^2 + 3.2t
where the height h is measured in feet, and the time t is measured in seconds.
After how many seconds does the ball land?
per second. The height of the ball is given by
h=-9.8t^2 + 3.2t
where the height h is measured in feet, and the time t is measured in seconds.
After how many seconds does the ball land?
Answers
Answered by
PsyDAG
The height will be 0. Insert into the equation and solve for t.