Asked by Danny
If the create has a mass of 90 kg and is 1.6 {\rm m} tall and 0.80 {\rm m} in depth and width, what is the minimum force needed to make the crate start tipping? (Assume the center of mass of the crate is at its center and static friction great enough to prevent slipping.)
Answers
Answered by
bobpursley
It matters where the force is applied. If it is applied at a top edge, then
summing forces about the bottom corner
Force*1.6=mass*g*.4
solve for force in newtons.
summing forces about the bottom corner
Force*1.6=mass*g*.4
solve for force in newtons.
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