angular acceleration
= (Torque)/(moment of inertia)
The units will be radians/s^2 if torque and moment of inertia are in the units given.
= (Torque)/(moment of inertia)
The units will be radians/s^2 if torque and moment of inertia are in the units given.
Given that the net torque is 1.6 N·m and the moment of inertia is 0.25 kg·m2, we can rearrange the formula to solve for α:
α = τ / I
Plugging in the values, we get:
α = 1.6 N·m / 0.25 kg·m2
Doing the math, we find that the angular acceleration of the blades is 6.4 rad/s².
So, there you have it. The blades are getting quite a twist with an angular acceleration of 6.4 rad/s². Just make sure to keep your eyes peeled for any flying clowns while you enjoy the breeze!
τ = I * α
Where τ is the net torque applied to the blades, I is the moment of inertia, and α is the angular acceleration.
Plugging in the given values, we have:
1.6 N·m = 0.25 kg·m^2 * α
Now we can solve for α:
α = 1.6 N·m / 0.25 kg·m^2
= (1.6 / 0.25) (N·m / kg·m^2)
= 6.4 (N·m / kg·m^2)
Therefore, the angular acceleration of the blades is 6.4 N·m / kg·m^2.
τ = I * α
In this case, the given net torque is 1.6 N·m and the moment of inertia is 0.25 kg·m². Substituting these values into the equation:
1.6 N·m = 0.25 kg·m² * α
To solve for α, divide both sides of the equation by 0.25 kg·m²:
α = 1.6 N·m / 0.25 kg·m²
Simplifying the equation gives:
α = 6.4 N·m /kg·m²
Therefore, the angular acceleration of the blades is 6.4 N·m /kg·m².