A 25 mL sample of wine is found to have a concentration of acetic acid of 0.23 M. If this was titrated with a 0.16 M NaOH solution how many mL's of NaOH would be required?

Answer 1

How many moles of acetic acid do you have. M x L = ??
How many moles NaOH will that require? It must be the same because the reaction between acetic acid and NaOH is 1:1.
Then moles NaOH = M x L; you have moles NaOH and M NaOH, solve for L.
For 1:1 reactions, the shorter mL x M = mL x M may be used.