Asked by bobjahng2
A laboratory centrifuge on earth makes n rpm (rev/min) and produces an acceleration of 3.30 g at its outer end.
This centrifuge is now used in a space capsule on the planet Mercury, where g mercury is 0.378 what it is on earth. How many rpm (in terms of n) should it make to produce 4 g mercury at its outer end?
This centrifuge is now used in a space capsule on the planet Mercury, where g mercury is 0.378 what it is on earth. How many rpm (in terms of n) should it make to produce 4 g mercury at its outer end?
Answers
Answered by
drwls
The centripetal acceleration is proportional to w^2 or rpm^2.
To increase the acceleration by a factor 4*0.378 = 1.512, the rotation rate must increase by a factor sqrt1.512 = 1.23
That would make it 1.23 n
To increase the acceleration by a factor 4*0.378 = 1.512, the rotation rate must increase by a factor sqrt1.512 = 1.23
That would make it 1.23 n
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