Question

Doing something wrong. Write an equation of the line containing the given point and perpendicular to the given line. (4,5;)4x+y=8; I tried this.

y = -4x+8. The slope is the reciprocal of -4 so 1/4. Then (y - y^1=m(x-x^1).
y -4 = 1/4(x-4). I then multiplied 1/4 and 4 then added -4 to both sides but still managed to get a wrong answer of 1/4x +5???

Answer 1

I agree that your line is of the form
y = (1/4)x + b

5 = 1 + b
b = 4

y = (x/4) + 4

Answer 2

Ok,I was one off. Thank you!!!