Asked by Roxanne
A 2.1 mm-long, 0.46 mg house flea can reach a height of 17 cm in a single leap.
I've found that, neglecting air speed, v = 1.8 m/s
How do I calculate the kinetic energy of this flea at takeoff & its kinetic energy per kilogram of mass? (to get K = __ J)
Thanks for helping!
I've found that, neglecting air speed, v = 1.8 m/s
How do I calculate the kinetic energy of this flea at takeoff & its kinetic energy per kilogram of mass? (to get K = __ J)
Thanks for helping!
Answers
Answered by
Damon
(1/2) m v^2 = m g h
v = sqrt (2*9.8*1.7) = 5.77 m/s
(I disagree with your speed)
Ke = (1/2) m v^2 = (1/2)(.46*10^-6 kg)(5.77^2)
= 7.99*10^-6 Joules
divide that by .46*10^-6 to get J/kg
= 16.7 J/kg
which is a lot !
v = sqrt (2*9.8*1.7) = 5.77 m/s
(I disagree with your speed)
Ke = (1/2) m v^2 = (1/2)(.46*10^-6 kg)(5.77^2)
= 7.99*10^-6 Joules
divide that by .46*10^-6 to get J/kg
= 16.7 J/kg
which is a lot !
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.