Question

I need to write an equation of the line containing the given point and parallel to the given line. in y = mx+b.
(-6,2;) 6x=5y+4

Answer 1

the slope of the given line is 6/5

so new equation is y = (6/5)x + b
but (-6,2) lies on it
2 = -36/5 + b
10 + 36 = 5b
b = 46/5

y = (6/5)x + 46/5

Answer 2

ok, thank you so much!