Asked by John
How many Al atoms thick is the aluminum foil if it is 0.00157cm thick.
1 Al atom = 286pm
Convert pm to m
286pm = 2.86*10^-10m
Convert m to cm
2.86*10^-10m = 2.9*10^-8cm
Divide aluminum thickness and Al atom thickness
1.57*10^-3 / 2.9*10^-10 = 54138
So the aluminum foil is 54138 Al atoms thick?
Am I correct? If not please correct me!
Thank you very much.
1 Al atom = 286pm
Convert pm to m
286pm = 2.86*10^-10m
Convert m to cm
2.86*10^-10m = 2.9*10^-8cm
Divide aluminum thickness and Al atom thickness
1.57*10^-3 / 2.9*10^-10 = 54138
So the aluminum foil is 54138 Al atoms thick?
Am I correct? If not please correct me!
Thank you very much.
Answers
Answered by
Dr Russ
1 Al atom = 286pm
Convert pm to m
286pm = 2.86*10^-10m
agreed
Convert cm to m
0.00157 cm
0.00157 cm/10^2 cm m^-1
=0.0000157 m
Divide aluminum thickness and Al atom thickness
1.57*10^-5 m / 2.9*10^-10 m = 54138 atoms
so looks OK. It is a good idea to keep units in calculations so you can make sure that the units cancel.
Convert pm to m
286pm = 2.86*10^-10m
agreed
Convert cm to m
0.00157 cm
0.00157 cm/10^2 cm m^-1
=0.0000157 m
Divide aluminum thickness and Al atom thickness
1.57*10^-5 m / 2.9*10^-10 m = 54138 atoms
so looks OK. It is a good idea to keep units in calculations so you can make sure that the units cancel.
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