Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A shotputter throws the shot with an initial speed of 15.5 m/s at a 32.0 degree angle to the horizontal. Calculate the horizont...Asked by steph
A shotputter throws the shot with an initial speed of 16.0 m/s at a 36.0 angle to the horizontal. Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.00 m above the ground
Answers
Answered by
Nathan
Hmm, I hate physic's, it messes with your head.
Answered by
drwls
Solve this equation for t.
Y = 2.00 + 16sin36*t - (g/2)t^2
and take the positive root for t.
g = 9.81 m/s^2, of course
Then multipy t by the horizontal velocity component, 16.0 cos 36 = 12.94 m/s
Y = 2.00 + 16sin36*t - (g/2)t^2
and take the positive root for t.
g = 9.81 m/s^2, of course
Then multipy t by the horizontal velocity component, 16.0 cos 36 = 12.94 m/s
Answered by
steph
36.1 is the answer i got
its wrong though
what could i have done wrong?
its wrong though
what could i have done wrong?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.