Asked by Cliff
Tutors: thanks for your help.
Is this how this problem is solved ?
A sample of Xenon gas at 20degrees celcius and 0.570atm is cooled to a pressure of 0.100atm. If the volume remains constant what is the final temperature in degree celcius?
Solution: Using Gay-Lussac's Law to find T2 or final temperature.
T2=P2T1/P1
=(0.100atm)(293kelvin)/0.570atm
=51.4kelvins
=51.4k - 273k
= - 222degrees celcius ??
And last question
If 0.105mol of He gas occupies a volume of 2.35L,what volume would 0.337 mol of He occupy?
Solution:
1 mole of a gas at STP = 22.4L
So, 0.337mol He * 22.4L/1 mol He = 7.55L.
Have a Good Evening.
Is this how this problem is solved ?
A sample of Xenon gas at 20degrees celcius and 0.570atm is cooled to a pressure of 0.100atm. If the volume remains constant what is the final temperature in degree celcius?
Solution: Using Gay-Lussac's Law to find T2 or final temperature.
T2=P2T1/P1
=(0.100atm)(293kelvin)/0.570atm
=51.4kelvins
=51.4k - 273k
= - 222degrees celcius ??
And last question
If 0.105mol of He gas occupies a volume of 2.35L,what volume would 0.337 mol of He occupy?
Solution:
1 mole of a gas at STP = 22.4L
So, 0.337mol He * 22.4L/1 mol He = 7.55L.
Have a Good Evening.
Answers
Answered by
MathMate
Both answers are correct.
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