Does the force push the 75 kg crate in the direction of the 113 kg crate, thereby moving both of them? That should have been made clear.
If so, the total friction force is
Ff1 + Ff2 = (75+113)*(0.15)*g = 276 N
The net force accelerating both crates is then
Fnet = 727 - 276 = 451 N
and they both accelerate together at a rate
a = Fnet/(75 + 113) = 2.4 m/s^2
There is a force F' that the two crates exert on each other. You can get it by considering the freebody diagram for either crate. For the 75 kg crate, denoted by "1",
727 N - Ff1 - F' = M1*a = 75*2.4 = 180 N
Ff1 = 0.15*Ma*g = 110 N
F' = 727 -110 -180 = ___
two crates, of mass 75 kg and 113 kg, are in contact and at rest on a horizontal surface. A 727 N force is exerted on the 75 kg crate.
If the coefficient of kinetic friction is 0.15, calculate the following:
a)the acceleration of the system
b) the force that each crate exerts on the other
1 answer
1 answer