Asked by Shannon
a certain brand of laundry aid called "Oxydoodle" is 12.5% (w/w) sodium percarbonate and 87.5% (w/w) sodium carbonate. Calculate the % (w/w) h2o2 in Oxydoodle
Answers
Answered by
DrBob222
I assume this dry compound is
12.5 g Na2CO3*1.5H2O2/[(12.5 g Na2CO3*1.5H2O2)+(87.5 g Na2CO3)]
So the real question is, how much H2O2 is in the 12.5 g. That will be
12.5 x (1.5 x molarmass H2O2)/(molarmass Na2CO3*1.5 H2O2)
12.5 g Na2CO3*1.5H2O2/[(12.5 g Na2CO3*1.5H2O2)+(87.5 g Na2CO3)]
So the real question is, how much H2O2 is in the 12.5 g. That will be
12.5 x (1.5 x molarmass H2O2)/(molarmass Na2CO3*1.5 H2O2)
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