Asked by Lisa
calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from
n=5 to n=1
how do I do this?
n=5 to n=1
how do I do this?
Answers
Answered by
DrBob222
E = 2.180E-18 J*(1/1^2 - 1/5^2)
Answered by
Lisa
I think I am doing something wrong.
I keep coming up with 8.72x10^17 and it is telling me I am wrong.
I know D E=2.18x10^-18 x (1/1^2-1/5^2)
I keep coming up with 8.72x10^17 and it is telling me I am wrong.
I know D E=2.18x10^-18 x (1/1^2-1/5^2)
Answered by
Lisa
i think I am not doing this part right
(1/n5^2 - 1/n1^2)
(1/n5^2 - 1/n1^2)
Answered by
Anonymous
2.0928 x 10(to the power of -18)
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