I responded to this in your earlier post except I see I used 5.56 g and not 5.58 g.
http://www.jiskha.com/display.cgi?id=1290380148
Nitric acid,HNO3, is available ata a concentration of 16 M. how much would react with 5.58 g of KOH acording to the following equation?
HNO3+KOH-H2O+KNO3
dont understand? does not give me a volume amount to work with and I really don't understand how to solve it
1 answer
1 answer