Asked by kevin Chen
A braking force is applied to a 300-kg motorcycle to reduce its speed from 20.0m/s to 16.0m/s in 10.0s. Find the braking force.
Answers
Answered by
Raymond
Deceleration:
16 = 20 + Ta
16 - 20 = 10a
a = -0.4 m/s2
Braking force = 300 X 0.4 = -120 N
Please check the above calc and give comments!
16 = 20 + Ta
16 - 20 = 10a
a = -0.4 m/s2
Braking force = 300 X 0.4 = -120 N
Please check the above calc and give comments!