Asked by Warren
A crate of mass 20 kg is pushed up a frictionless ramp by a person as shown in the figure below. Calculate the work done by the person in pushing the crate a distance of 15 m as measured along the ramp. Assume the crate moves at a constant velocity.
Answers
Answered by
nona
The work done = Force X displacement in the direction of the force.
The sum of forces in the horizontal direction is mgSin(of the angle)- F = 0
The force acting, F = mgSin(of the angle).
The Work done by this force = mgSin(of the angle) X 15 meters
The Work done = 20 X 9.8 X Sin(of the angle of inclination of the ramp) X 15
The sum of forces in the horizontal direction is mgSin(of the angle)- F = 0
The force acting, F = mgSin(of the angle).
The Work done by this force = mgSin(of the angle) X 15 meters
The Work done = 20 X 9.8 X Sin(of the angle of inclination of the ramp) X 15
Answered by
Jess
A crate of mass 32 kg is pushed up a frictionless ramp by a person as shown in the figure below. Calculate the work done by the person in pushing the crate a distance of 25 m as measured along the ramp. Assume the crate moves at a constant velocity.
Answered by
Anonymous
Calculate how much work linda does on the crate if she exerts a force of a 120N at an angle of 30 with the ground on the crate
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