Asked by fred
A 3700 kg statue is placed on top of a cylindrical concrete (Y = 2.3 1010 N/m2) stand. The stand has a cross-sectional area of 7.2 10-2 m2 and a height of 2.0 m. By how much does the statue compress the stand?
Answers
Answered by
drwls
They give you Young's moduls of the concrete, Y = 2.3*10^10 N/m^2
The pedestal area is A = 7.2*10^-2 m^2
Use the elastic law that
stress = (strain)*Y
In this case,
strain = compression/length
Therefore
compression = Length*strain
= Length*stress/Y
= Length *(weight)/[(area)*Y]
Don't forget that weight = M g, so
compression = L M g/[(area)*Y]
The pedestal area is A = 7.2*10^-2 m^2
Use the elastic law that
stress = (strain)*Y
In this case,
strain = compression/length
Therefore
compression = Length*strain
= Length*stress/Y
= Length *(weight)/[(area)*Y]
Don't forget that weight = M g, so
compression = L M g/[(area)*Y]
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