Asked by Jess
A scuba diver creates a spherical bubble with a radius of 4.0 at a depth of 30.0 where the total pressure (including atmospheric pressure) is 4.00 .
What is the radius of the bubble when it reaches the surface of the water? (Assume atmospheric pressure to be 1.00 and the temperature to be 298 .)
What is the radius of the bubble when it reaches the surface of the water? (Assume atmospheric pressure to be 1.00 and the temperature to be 298 .)
Answers
Answered by
Jess
the 4.0 is cm, depth is 30 m, and pressure is 4.00atm
Answered by
DrBob222
Convert 4 cm radius to volume. volume of sphere is (4/3)*pi*r^3
Use PV = nRT to solve for n but you need temperature at the depths which isn't listed in your post.
After finding n, use PV = nRT at the new conditions and solve for volume, then convert to radius. Frankly, I don't think the problem is solvable without knowing the temperature of the water at 30 meters.
Use PV = nRT to solve for n but you need temperature at the depths which isn't listed in your post.
After finding n, use PV = nRT at the new conditions and solve for volume, then convert to radius. Frankly, I don't think the problem is solvable without knowing the temperature of the water at 30 meters.
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