Question
A kettle heats up 1.5L of water from 22 degreesC to 90 degreesC in 4 min. What power did the water receive?
Answers
drwls
Divide the energy absorbed (in Joules) by the time interval (in seconds). The answer will be in Watts.
The heat energy transferred to water is: Q = M*C*(delta T), where
M = 1.5 kg
C = 4184 J/(kg*degC)
deltaT = 68 C
time interval = 240 s
The heat energy transferred to water is: Q = M*C*(delta T), where
M = 1.5 kg
C = 4184 J/(kg*degC)
deltaT = 68 C
time interval = 240 s