Asked by aok

A 0.38-kg mass attached to a spring undergoes simple harmonic motion with a period of 0.63 s. What is the force constant of the spring?
Answered by drwls
Period = 2*pi*sqrt(m/k)

Solve for k.

m/k = [P/(2 pi)]^2

k = ?
Answered by Anonymous
I tried that formula, and double checked it. My answer was nowhere near correct.
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