A 0.38-kg mass attached to a spring undergoes simple harmonic motion with a period of 0.63 s. What is the force constant of the spring?

Answer 1

Period = 2*pi*sqrt(m/k)

Solve for k.

m/k = [P/(2 pi)]^2

k = ?

Answer 2

I tried that formula, and double checked it. My answer was nowhere near correct.