Asked by mel
how much of each of the following substances would you add to water to prepare 1.20L of a .85M solution? (H2SO4 from "concentrated" (18M) sulfuric acid) ? I am stuck on how to work this one out. thanks
Answers
Answered by
DrBob222
Two ways to do it.
18 M = 18 mols per liter.
You want 1.20 L x 0.85 M = 1.02 mols.
Then L x M = mols.
L x 18 = 1.02
L = ?? of H2SO4.
OR you can use the dilution formula.
L x M = L x M
L x 18 M = 1.20 L x 0.85 M
solve for Liters of H2SO4 @ 18 M.
18 M = 18 mols per liter.
You want 1.20 L x 0.85 M = 1.02 mols.
Then L x M = mols.
L x 18 = 1.02
L = ?? of H2SO4.
OR you can use the dilution formula.
L x M = L x M
L x 18 M = 1.20 L x 0.85 M
solve for Liters of H2SO4 @ 18 M.
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