Asked by alejandrob

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. Unfortunately the archer stands on an elevated platform of unknown height. However, you find the arrow stuck in the ground 62.0 m away, making a 2.00 degree angle with the ground.

How fast was the arrow shooting?
Answered by bobpursley
Trig: horizontal distance=62
vertical distance=62*tan2

time to fall vertical distance...

h=1/2 g t^2
62*tan2=1/2 g t^2 solve for t.

speed= 62/t
Answered by alejandrob
i get 93, but my hw says its wrong
Answered by spoerl
same question with different numbers cant get the answer don't think that's the right equation to use
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