Asked by flame
An antelope is at a distance of 20.0 m from a converging lens of focal length 32.0 cm. The lens forms an image of the animal. If the antelope runs towards the lens at a speed of 5.50 m/s, what is the speed with which the image moves?
1/q= 1/32cm-1/2000cm
q=32.5203252
dq/dt=-(32.5203252/2000)^2 *5.50m/s=-1.45mm/s(the sign does not mater), i don't get why this is wrong
1/q= 1/32cm-1/2000cm
q=32.5203252
dq/dt=-(32.5203252/2000)^2 *5.50m/s=-1.45mm/s(the sign does not mater), i don't get why this is wrong
Answers
Answered by
Anonymous
You have the equations correct but the answer is wrong by a multiple of ten. Do the problem again, but all in meters and change it to mm in the end.
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