Question

whats the pH if 25.0 ml of 2.0 M NaOH is added to 1.00 L of pure water?
First calculate the molarity of the NaOH. It is diluted 25 mL to 1,025 mL. So 2.0 M x (25/1025) = ??
NaOH is a strong electrolyte and is ionized 100%; therefore, OH^- = the molarity. Take it from here with the following:
pOH = - log (OH^-)
pH + pOH = 14.
Pure water is added to 25.0 mL of a 1.00 M HCL solution. The new solution has a volume of 2.00 L. What is the pH of the new solution.

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