Asked by gull
a proton starting from rest falls through a potential difference of 10^6v what is its final KE and final velocity?
Answers
Answered by
bobpursley
Energy= Voltage*q where q is the charge on a the proton.
VQ= 1/2 m v^2 solve for velocity.
VQ= 1/2 m v^2 solve for velocity.
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