Asked by Jon
A cowboy at a ranch fills a water trough that is 1.1 m long, 62 cm wide, and 48 cm deep. He uses a hose having a diameter of 2.4 cm, and the water emerges from the hose at 2.4 m/s.
How long does it take the cowboy to fill the trough?
Answer in units of s.
How long does it take the cowboy to fill the trough?
Answer in units of s.
Answers
Answered by
bobpursley
Volume tank= 1.1*.62*height
DV/dt= 1.1*.62 dh/dt
Hose: dv/dt= area*velocity
areahose*velocity= 1.1*.62*dh/dt
itegrate over time
areahose*velocity*time= 1.1*.62*h
solve for time.
DV/dt= 1.1*.62 dh/dt
Hose: dv/dt= area*velocity
areahose*velocity= 1.1*.62*dh/dt
itegrate over time
areahose*velocity*time= 1.1*.62*h
solve for time.
Answered by
yo
Volume= l * W *h in meters
Velocity= 2.4 m/s
Area= (pi)(r^2)
Flow rate= Velocity times area
Time= Volume/Flow Rate
Velocity= 2.4 m/s
Area= (pi)(r^2)
Flow rate= Velocity times area
Time= Volume/Flow Rate
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