Question

Determine the amount concentration of the iron ions and sulfate ions in a 0.620 mol/L solution of iron(III) sulfate.

Including the balanced chemical equation.

Answer 1

There is no equation to balance.
Fe2(SO4)3 ==> 2Fe^+3 + 3SO4^-2

So I look at 0.620 M Fe2(SO4)3.
So Fe^+3 must be twice that
and SO4^-2 must be three times that. right?
Don't make problems any harder than they need to be.;-)

Answer 2

thank you