Question
An unknown weak monprotic acid with the general formula HA has a Ka=5.5 x 10^-7. what is the value of the equilibrium constant that describes the following reaction?
A- +H2O = HA +OH-
A- +H2O = HA +OH-
Answers
DrBob222
Keq = (HA)(OH^&-)/(A^-)(H2O)