Asked by Ron

Nitrous acid, HNO2, has a Ka of 7.1 x 10^-4. what are [H3O+], [NO2-], and [OH-] in .920 M HNO2?

Answers

Answered by DrBob222
HNO2 ==> H^+ + NO2^-

Ka = (H^+)(NO2^-)/(HNO2) = 7.1E-4

Set up ICE chart. H^+ = x, NO2^- x, HNO2 = 0.920-x and solve for x, convert to pH, then I would convert to pOH, then to OH^-. x will give the other values. 0.920-x will give you HNO2.
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