Question
Nitrous acid, HNO2, has a Ka of 7.1 x 10^-4. what are [H3O+], [NO2-], and [OH-] in .920 M HNO2?
Answers
DrBob222
HNO2 ==> H^+ + NO2^-
Ka = (H^+)(NO2^-)/(HNO2) = 7.1E-4
Set up ICE chart. H^+ = x, NO2^- x, HNO2 = 0.920-x and solve for x, convert to pH, then I would convert to pOH, then to OH^-. x will give the other values. 0.920-x will give you HNO2.
Ka = (H^+)(NO2^-)/(HNO2) = 7.1E-4
Set up ICE chart. H^+ = x, NO2^- x, HNO2 = 0.920-x and solve for x, convert to pH, then I would convert to pOH, then to OH^-. x will give the other values. 0.920-x will give you HNO2.