Asked by bobby
How many moles of negative ions are in 33.7 g of AlF3?
Answers
Answered by
DrBob222
moles AlF3 = grams/molar mass = 33.7 g/molar mass AlF3 = ?? moles.
??moles F = ??moles AlF3 x (3 moles F^-/1 mole AlF3) = xx.
??moles F = ??moles AlF3 x (3 moles F^-/1 mole AlF3) = xx.
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