Asked by Mayte


Suppose two blocks of ice are heading toward each other. block A has a mass of 4.24 kg and is traveling at 2.24 m/s. Block B has a mass 4.42 kg and is traveling at 2.24 m/s in the opposite direction. After the collision they are traveling in the same speed. what is the speed they are traveling?
Answered by bobpursley
conservation of momentum.

Ma*4.24+ Mb(-2.24)= (Ma+Mb) V
solve for V
Answered by Mayte

Suppose two blocks of ice are heading toward each other. block A has a mass of 4.24 kg and is traveling at 2.24 m/s. Block B has a mass 4.42 kg and is traveling at 2.24 m/s in the opposite direction. After the collision they are traveling in the same speed. what is the speed they are traveling?

Ma*4.24 + Mb(-2.24)= (Ma+Mb)V
4.24 + -2.24 = (4.42 + 2.24)V
2= (6.66)V
-4.66 = V

Is this correct?
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