Asked by Erin
If the amount of raidoactive iodine-123 in a sample decreases from 0.4 to 0.1 g in 26.2 hours, what is the half-life of iodine-123?
Answers
Answered by
DrBob222
ln(No/N) = kt
No = 0.4
N = 0.1
t = 26.2 hours.
Solve for k. Then
k = 0.693/t<sub>1/2</sub>
Solve for t<sub>1/2>/sub>
No = 0.4
N = 0.1
t = 26.2 hours.
Solve for k. Then
k = 0.693/t<sub>1/2</sub>
Solve for t<sub>1/2>/sub>
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