Question

r+s=5 3s+2t=-1 4r+t=14 ican u breakdown the answer I get half way though i forgot the last pat wheater i put it back into the original equationn alot of steps i get lost

Answer 1

Eq1: r + s = 5.

Eq2: 3s + 2t = -1.

Eq3: 4r + t = 14.

Solve for s in Eq1:
s = 5 - r.

Substitute 5 - r for s in Eq2:

3(5 - r) + 2t = -1,
15 - 3r + 2t = -1,
-3r + 2t = -1 -15,
Eq4: -3r + 2t = - 16.

Multiply Eq3 by -2 and add Eq3 and Eq4:

Eq3M2: -8r - 2t = -28,
Eq4: -3r + 2r = -16,
Eq3+Eq4:-11r = -44,
r = 4.

Substitute 4 for r in Eq3:
Eq3: 4*4 + t = 14,
16 + t = 14,
t = 14 - 16,
t = - 2.

Substitute 4 for r in Eq1:
Eq1: 4 + s = 5,
s = 5 - 4,
s = 1.

Solution Set: r = 4, s = 1, and t = -2.