Asked by Juliet
How would you solve an exponential equation like this...
2^(3x+1)= 3^(x-2)
2^(3x+1)= 3^(x-2)
Answers
Answered by
MathMate
Take log on both sides to get:
(3x+1)log2 = (x-2)log3
Solve for x.
Log can be to any base.
(3x+1)log2 = (x-2)log3
Solve for x.
Log can be to any base.
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