Question
A .5kg ball on the end of a string is revolving uniformly in ahorizontal circle of radius 1m. The ball makes 2 revolustion in a second.
a) determine the linear (tangential) speed of the ball.
For this part of the question would I do this:
v=d/t
=1m/.5s
=2m/s
b)determine the ball's centripetal acceleration
a_c=v^2/r
=2m/s^2/1
=4m/s^2
c)determine the force a person must exert on the opposite end of the string.
F_c=mv^2/r
=.5kg(2m/s)^2/1
=2N
Is this correct? The only thing i'm not too sure about is part a). Thanks in advance for your help.
a) determine the linear (tangential) speed of the ball.
For this part of the question would I do this:
v=d/t
=1m/.5s
=2m/s
b)determine the ball's centripetal acceleration
a_c=v^2/r
=2m/s^2/1
=4m/s^2
c)determine the force a person must exert on the opposite end of the string.
F_c=mv^2/r
=.5kg(2m/s)^2/1
=2N
Is this correct? The only thing i'm not too sure about is part a). Thanks in advance for your help.
Answers
bobpursley
The distance around the circle is 2PI*radius, v= distance/time You have distance equal to radius.
The centripetal force is indeed v^2/r, your numbers are of course wrong.
part A messes up part b, c.
The centripetal force is indeed v^2/r, your numbers are of course wrong.
part A messes up part b, c.