Asked by pam
A 1.20-L container contains 1.10 g of unknown gas at STP.What is the molecular weight of the unknown gas?
Answers
Answered by
bobpursley
hmmmm. At STP a mole of any gas occupies 22.4 liters, so
1.20/?moles=22.4/1mole
solve for ? moles, then
?moles=1.10g/molmass solve for molmass.
1.20/?moles=22.4/1mole
solve for ? moles, then
?moles=1.10g/molmass solve for molmass.
Answered by
pam
1.10g/mole
Answered by
Red
1.20 L*1 mole/22.4 L= 0.05357 moles
L units cx out.
Then use your given mass of
1.10 g/0.05357 moles=20.5 g/mole
L units cx out.
Then use your given mass of
1.10 g/0.05357 moles=20.5 g/mole
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