Asked by bjisa
A sample of Limonene has a specific rotation of +76.9. What is the % ee and
molecular composition of this sample? R(+)- is +125.6 and S (-)- 122.1. I'm confused I don't know whether I should divided by 125.6 or 122.1. %ee=(76.9/125.6)*100=61%. Is this correct? I'm clueless as to how to find the molecular composition
molecular composition of this sample? R(+)- is +125.6 and S (-)- 122.1. I'm confused I don't know whether I should divided by 125.6 or 122.1. %ee=(76.9/125.6)*100=61%. Is this correct? I'm clueless as to how to find the molecular composition
Answers
Answered by
World cup
I also have the same question for hw. Ibelieve you do divide by 125.6 since dividing by same sign. For molecular composition, I think it is saying 100-61.2= 38.8% and since this is a mixture of both R and S you give half on each side.
Thus R: 61.2 + 19.4= 80.6% composition
S: 19.4% composition
I hoping this is right. Goodluck
Thus R: 61.2 + 19.4= 80.6% composition
S: 19.4% composition
I hoping this is right. Goodluck
Answered by
natalie
thank you so much
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