Question

A husband and wife take turns pulling their child in a wagon along a horizontal sidewalk. Each exerts a constant force and pulls the wagon through the same displacement. They do the same amount of work, but the husband's pulling force is directed 50° above the horizontal, and the wife's pulling force is directed 31° above the horizontal. The husband pulls with a force whose magnitude is 62 N. What is the magnitude of the pulling force exerted by his wife?

Answers

Since they do the same amount of work pulling equal distances, they both pull with the same force component along the horizontal direction of motion.

F(man)*cos 50 = F(woman)*cos31

F(woman) = F(man)*[cos50/cos31]
0.21

Related Questions