Question

lim y^3-y^2-y-2/2y^3-5y^2+5y-6
y-->2

Answer 1

Have you tried these yourself? For the first couple you just plug in the value of the variable. No limit process is necessary.

for this one
Now I bet that y-2 is a factor of both top and bottom or the denominator would not go to zero causing our problem to be non trivial at y = 2

So try dividing top and bottom by (y-2)
for the numerator I get y^2+y+1
for the denominator I get 2y^2-y+3

so I have at y = 2
(4+2+1)/(8-2+3)

7/9