Asked by Adam
Evaluate
The integral from 0 to 5 of (t)(e^-t)dt.
I got -5e^-5+-e^-5, but this is incorrect.
The integral from 0 to 5 of (t)(e^-t)dt.
I got -5e^-5+-e^-5, but this is incorrect.
Answers
Answered by
Reiny
After integration by parts I got
-te^-t - e^-t
which from 0 to 5 gave me
-5e^-5 - e^-5 - [0 - e^0]
= -5e^-5 - e^-5 + 1
-te^-t - e^-t
which from 0 to 5 gave me
-5e^-5 - e^-5 - [0 - e^0]
= -5e^-5 - e^-5 + 1
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