Asked by JP

Consider the evaporation of methanol at 25.0 c: CH3OH(l)-- CH3OH(g)
I figured out that Delta G is 4.3 kJ.

Find the Delta G at 25 C under the following conditions:

Pressure of CH3OH= 157mmHg, 103mmHg, 14mmHg

thanks! please explain
Answered by Anonymous
Thank you for finding the delta G for me so here is how to solve this problem,

Formula: Delta G(rxn)= DeltaG(rxn)^degree + RTlnQ
1 atm = 760 mmHg

4300J + 8.314*298K*ln(157/760)=
tyvm again.

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