Question

you decide to have a BBQ in your backyard. you have 1Kg of pentane (C5H12) in the tank. What is the amount of carbon dioxide (in mass and mols) you will be contributing to the greenhouse gas effect by using up that 1Kg of pentane?


plz.... need the answer with steps...thank you



C5H12 + 8O2 -----> 5CO2 + 6H2O

i balance the equation i hope itis right.

Answer 1

This is a stoiciometry question!
You have the correct chemical equation already so:
First calculate the number of moles of Pentane, than use stoiciometry to figure out the number of moles of CO2 produced and finally convert it to mass using the molar mass.
Do you know how to figure out the molar mass? because i will not include that part in tha calculations.
step one: (mol of pentane/72.17 g) * 1000g = 13.86 moles of pentane.
step two: (13.86 moles of pentane) * (5 mol(CO2)/1 mol(Pentane)) = 69.28 moles of carbon dioxide.
Step three: (69.28 moles of carbon dioxide) * (44.01 g/mol) = 3.05 Kg of carbon dioxide.
Enjoy the rest of your stoiciometry!!