Asked by Kyo
The given reaction,
2N2O5 4NO2 + O2,
follows first-order kinetics and has an activation energy of 103 kJ mol-1. At 298 K, k = 0.0000354 s-1. What is the half-life (min) for this reaction at 338 K ? Round your answer to 3 significant figures.
2N2O5 4NO2 + O2,
follows first-order kinetics and has an activation energy of 103 kJ mol-1. At 298 K, k = 0.0000354 s-1. What is the half-life (min) for this reaction at 338 K ? Round your answer to 3 significant figures.
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
Substitute for k and calculate t<sub>1/2</sub>.
Substitute for k and calculate t<sub>1/2</sub>.
Answered by
Kyo
?? and then what do you do?
.0000354 = 0.693/t(1/2)
t(1/2) = 19576.27119
.0000354 = 0.693/t(1/2)
t(1/2) = 19576.27119
Answered by
Kyo
the answer is suppose to be 2.38 min
Answered by
teddy
which isomer Maleic acid or fumanic acid has the strongest intermolecular bonding? why?
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