Asked by clueless
A 27.0 kg child on a 3.00 m long swing is released from rest when the swing supports make an angle of 31.0° with the vertical. Neglecting friction, find the child's speed at the lowest position.
Answers
Answered by
Damon
mass is irrelevant for pendulum, cancels
Figure out how high the child is above the low point when the chains are 31 deg from vertical
h = 3 (1 - cos 31)
U at top = m g h
Ke at bottom = U at to
(1/2) m v^2 = m g h
v = sqrt (2 g h)
Figure out how high the child is above the low point when the chains are 31 deg from vertical
h = 3 (1 - cos 31)
U at top = m g h
Ke at bottom = U at to
(1/2) m v^2 = m g h
v = sqrt (2 g h)
Answered by
clueless
thanks!
Answered by
clueless
If the speed of the child at the lowest position is 2.50 m/s, what is the mechanical energy lost due to friction?
Answered by
bobpursley
mechanical energy lost= PE at top-1/2 m vb^2 where vb is the speed at the bottom
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