Question
A ball (m=53g) is projected vertically with an initial speed of 9.2m/s. If the ball rises to a maximum height of 3.6m, how much kinetic energy is dissipated by the drag force of air resistance? I know it is .373J
How much higher would the ball have gone in a vacuum??
How much higher would the ball have gone in a vacuum??
Answers
bobpursley
it had initial KE of 1/2 m v^2 (compute that). It ended up a the top with PE of mgh (compute that). The difference was dissipated by drag.
how high would it have gone?
mgh= 1/2 m v^2 solve for h.
how high would it have gone?
mgh= 1/2 m v^2 solve for h.