A boulder with a mass of 2,500 kg on a ledge 200 m above the ground falls. If the boulder's mechanical energy is conserved, what is the speed of the boulder just before it hits the ground?

Answer 1

1/2 m vf^2=m*g*height
solve for vf

notice mass divides out.

vf=sqrt(2gh)

Answer 2

How do you figure miles per hour?

Answer 3

what do you mean, Adam?

Answer 4

I meant meters per second