Question

A steel cylinder has a base with a radius of 10 cm and height of 8 cm. If the density of the cylinder is 8,000 kg/m3 , find the mass of the cylinder in kilograms. Use π=3.14 and round your answer to the nearest tenth.(1 point)
kg

Answer 1

Volume = πr^2h = 3.14*(0.10 m)^2*(0.08 m) = 0.0008·3.14 = 0.002512 m^3.
Mass = density·volume = 8000 kg/m^3 * 0.002512 m^3 = 20.096 kg ≈ 20.1 kg.